KenD Wrote:PJW Wrote:Whatever the value is, this is the closest spacing of 3 aspect signals and therefore lowest possible headway distance is then derived by:Shouldn't the value be divided by the speed of the train?
double signal spacing + sighting distance + train length + overlap length. Convert this to headway time by multiplying by the timetabled speed of the train (i.e. could be the maximum train speed but may be less). Then, as you have said, you need to ensure that there is an appropriate % contingency to arrive at the timetabled headway.
Oops- I changed the way this sentence worded and failed to re-read through. Yes headway distance (m) obviously must be DIVIDED by speed (m/s) in order to get a time (s)!
PJW

